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Limit of the function
:
Limit of (9+3*x^2+4*x)/(7-7*x+3*x^2)
Limit of (1+2*n)/(-1+3*n)
Limit of (x^3-3^x)/(-3+x)
Limit of -x+(-2+x)^4/(3+x)^4
Derivative of
:
2*x^5
Identical expressions
two *x^ five
2 multiply by x to the power of 5
two multiply by x to the power of five
2*x5
2*x⁵
2x^5
2x5
Similar expressions
((3+2*x)/(1+2*x))^(5+3*x)
2-x^2-5*x^3+2*x^5-x^4/3
(1-1/(3+2*x))^(5+x)
(1+3/(2*x))^(5*x)
Limit of the function
/
2*x^5
Limit of the function 2*x^5
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
/ 5\ lim \2*x / x->oo
$$\lim_{x \to \infty}\left(2 x^{5}\right)$$
Limit(2*x^5, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(2 x^{5}\right)$$
Let's divide numerator and denominator by x^5:
$$\lim_{x \to \infty}\left(2 x^{5}\right)$$ =
$$\lim_{x \to \infty} \frac{1}{\frac{1}{2} \frac{1}{x^{5}}}$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty} \frac{1}{\frac{1}{2} \frac{1}{x^{5}}} = \lim_{u \to 0^+}\left(\frac{2}{u^{5}}\right)$$
=
$$\frac{2}{0} = \infty$$
The final answer:
$$\lim_{x \to \infty}\left(2 x^{5}\right) = \infty$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
oo
$$\infty$$
Expand and simplify
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(2 x^{5}\right) = \infty$$
$$\lim_{x \to 0^-}\left(2 x^{5}\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(2 x^{5}\right) = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(2 x^{5}\right) = 2$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(2 x^{5}\right) = 2$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(2 x^{5}\right) = -\infty$$
More at x→-oo
The graph