Let's take the limit x→∞lim(3x5) Let's divide numerator and denominator by x^5: x→∞lim(3x5) = x→∞lim31x511 Do Replacement u=x1 then x→∞lim31x511=u→0+lim(u53) = 03=∞
The final answer: x→∞lim(3x5)=∞
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type