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Limit of the function
:
Limit of (-2*x^2+4*x^3+5*x)/(3*x^2+7*x)
Limit of (-cos(5*x)+cos(3*x))/x^2
Limit of (-1+cos(7*x))/(-1+cos(3*x))
Limit of (16+x^2+10*x)/(-6+x^2-x)
Sum of series
:
3/n
Identical expressions
three /n
3 divide by n
three divide by n
Similar expressions
(1+n)^(1/3)/n^(1/3)
Limit of the function
/
3/n
Limit of the function 3/n
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
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Piecewise:
{
enter the piecewise function here
The solution
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[src]
/3\ lim |-| n->oo\n/
$$\lim_{n \to \infty}\left(\frac{3}{n}\right)$$
Limit(3/n, n, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{n \to \infty}\left(\frac{3}{n}\right)$$
Let's divide numerator and denominator by n:
$$\lim_{n \to \infty}\left(\frac{3}{n}\right)$$ =
$$\lim_{n \to \infty}\left(\frac{3 \frac{1}{n}}{1}\right)$$
Do Replacement
$$u = \frac{1}{n}$$
then
$$\lim_{n \to \infty}\left(\frac{3 \frac{1}{n}}{1}\right) = \lim_{u \to 0^+}\left(3 u\right)$$
=
$$0 \cdot 3 = 0$$
The final answer:
$$\lim_{n \to \infty}\left(\frac{3}{n}\right) = 0$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Other limits n→0, -oo, +oo, 1
$$\lim_{n \to \infty}\left(\frac{3}{n}\right) = 0$$
$$\lim_{n \to 0^-}\left(\frac{3}{n}\right) = -\infty$$
More at n→0 from the left
$$\lim_{n \to 0^+}\left(\frac{3}{n}\right) = \infty$$
More at n→0 from the right
$$\lim_{n \to 1^-}\left(\frac{3}{n}\right) = 3$$
More at n→1 from the left
$$\lim_{n \to 1^+}\left(\frac{3}{n}\right) = 3$$
More at n→1 from the right
$$\lim_{n \to -\infty}\left(\frac{3}{n}\right) = 0$$
More at n→-oo
Rapid solution
[src]
0
$$0$$
Expand and simplify
The graph