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Limit of the function sqrt(x)+sqrt(4-x)

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     /  ___     _______\
 lim \\/ x  + \/ 4 - x /
x->oo                   
limx(x+4x)\lim_{x \to \infty}\left(\sqrt{x} + \sqrt{4 - x}\right)
Limit(sqrt(x) + sqrt(4 - x), x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
02468-8-6-4-2-10102.03.0
Rapid solution [src]
oo*sign(1 + I)
sign(1+i)\infty \operatorname{sign}{\left(1 + i \right)}
Other limits x→0, -oo, +oo, 1
limx(x+4x)=sign(1+i)\lim_{x \to \infty}\left(\sqrt{x} + \sqrt{4 - x}\right) = \infty \operatorname{sign}{\left(1 + i \right)}
limx0(x+4x)=2\lim_{x \to 0^-}\left(\sqrt{x} + \sqrt{4 - x}\right) = 2
More at x→0 from the left
limx0+(x+4x)=2\lim_{x \to 0^+}\left(\sqrt{x} + \sqrt{4 - x}\right) = 2
More at x→0 from the right
limx1(x+4x)=1+3\lim_{x \to 1^-}\left(\sqrt{x} + \sqrt{4 - x}\right) = 1 + \sqrt{3}
More at x→1 from the left
limx1+(x+4x)=1+3\lim_{x \to 1^+}\left(\sqrt{x} + \sqrt{4 - x}\right) = 1 + \sqrt{3}
More at x→1 from the right
limx(x+4x)=sign(1+i)\lim_{x \to -\infty}\left(\sqrt{x} + \sqrt{4 - x}\right) = \infty \operatorname{sign}{\left(1 + i \right)}
More at x→-oo