/ __________\
|\/ sin(2*x) |
lim |------------|
x->0+\ x /
x→0+lim(xsin(2x))
Limit(sqrt(sin(2*x))/x, x, 0)
Lopital's rule
We have indeterminateness of type
0/0,
i.e. limit for the numerator is x→0+limsin(2x)=0 and limit for the denominator is x→0+limx=0 Let's take derivatives of the numerator and denominator until we eliminate indeterninateness. x→0+lim(xsin(2x)) = x→0+lim(dxdxdxdsin(2x)) = x→0+lim(sin(2x)cos(2x)) = x→0+limsin(2x)1 = x→0+limsin(2x)1 = ∞ It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)