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sin(3)^2/sin(2)^2

Limit of the function sin(3)^2/sin(2)^2

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The solution

You have entered [src]
     /   2   \
     |sin (3)|
 lim |-------|
x->0+|   2   |
     \sin (2)/
$$\lim_{x \to 0^+}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right)$$
Limit(sin(3)^2/sin(2)^2, x, 0)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
   2   
sin (3)
-------
   2   
sin (2)
$$\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 0^-}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right) = \frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right) = \frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
$$\lim_{x \to \infty}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right) = \frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
More at x→oo
$$\lim_{x \to 1^-}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right) = \frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right) = \frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right) = \frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
More at x→-oo
One‐sided limits [src]
     /   2   \
     |sin (3)|
 lim |-------|
x->0+|   2   |
     \sin (2)/
$$\lim_{x \to 0^+}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right)$$
   2   
sin (3)
-------
   2   
sin (2)
$$\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
= 0.0240860321094052
     /   2   \
     |sin (3)|
 lim |-------|
x->0-|   2   |
     \sin (2)/
$$\lim_{x \to 0^-}\left(\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}\right)$$
   2   
sin (3)
-------
   2   
sin (2)
$$\frac{\sin^{2}{\left(3 \right)}}{\sin^{2}{\left(2 \right)}}$$
= 0.0240860321094052
= 0.0240860321094052
Numerical answer [src]
0.0240860321094052
0.0240860321094052
The graph
Limit of the function sin(3)^2/sin(2)^2