We have indeterminateness of type
0/0,
i.e. limit for the numerator is
x→0+limsin(sin(sin(x)))=0and limit for the denominator is
x→0+limx=0Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
x→0+lim(xsin(sin(sin(x))))=
x→0+lim(dxdxdxdsin(sin(sin(x))))=
x→0+lim(cos(x)cos(sin(x))cos(sin(sin(x))))=
x→0+lim1=
x→0+lim1=
1It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)