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Limit of the function
:
Limit of (-3*e^(4*x)-2*e^(-x)+5*e^(2*x))/(-4*sqrt(1+5*x)+4*cos(3*x)+5*sin(2*x))
Limit of (x/2)^(5/(-2+x))
Limit of (-4+x^2)/(6+x^2+5*x)
Limit of ((-1+x)/(1+x))^(1+x)
Derivative of
:
7/x^2
Identical expressions
seven /x^ two
7 divide by x squared
seven divide by x to the power of two
7/x2
7/x²
7/x to the power of 2
7 divide by x^2
Limit of the function
/
7/x^2
Limit of the function 7/x^2
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
/7 \ lim |--| x->oo| 2| \x /
$$\lim_{x \to \infty}\left(\frac{7}{x^{2}}\right)$$
Limit(7/x^2, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(\frac{7}{x^{2}}\right)$$
Let's divide numerator and denominator by x^2:
$$\lim_{x \to \infty}\left(\frac{7}{x^{2}}\right)$$ =
$$\lim_{x \to \infty}\left(\frac{7 \frac{1}{x^{2}}}{1}\right)$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty}\left(\frac{7 \frac{1}{x^{2}}}{1}\right) = \lim_{u \to 0^+}\left(7 u^{2}\right)$$
=
$$7 \cdot 0^{2} = 0$$
The final answer:
$$\lim_{x \to \infty}\left(\frac{7}{x^{2}}\right) = 0$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(\frac{7}{x^{2}}\right) = 0$$
$$\lim_{x \to 0^-}\left(\frac{7}{x^{2}}\right) = \infty$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\frac{7}{x^{2}}\right) = \infty$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(\frac{7}{x^{2}}\right) = 7$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\frac{7}{x^{2}}\right) = 7$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\frac{7}{x^{2}}\right) = 0$$
More at x→-oo
Rapid solution
[src]
0
$$0$$
Expand and simplify
The graph