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Limit of the function
:
Limit of (sin(3*x)^2-sin(x)^2)/x^2
Limit of ((1+x)/(-2+x))^(3+x)
Limit of ((1+x)/(2+x))^(1+x)
Limit of ((1+x)^3-(-1+x)^3)/(1+x^2)
Sum of series
:
7/2
The double integral of
:
7/2
Identical expressions
seven / two
7 divide by 2
seven divide by two
Limit of the function
/
7/2
Limit of the function 7/2
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
lim (7/2) x->oo
lim
x
→
∞
7
2
\lim_{x \to \infty} \frac{7}{2}
x
→
∞
lim
2
7
Limit(7/2, x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
-0.010
-0.008
-0.006
-0.004
-0.002
0.010
0.000
0.002
0.004
0.006
0.008
0.00
Plot the graph
Other limits x→0, -oo, +oo, 1
lim
x
→
∞
7
2
=
7
2
\lim_{x \to \infty} \frac{7}{2} = \frac{7}{2}
x
→
∞
lim
2
7
=
2
7
lim
x
→
0
−
7
2
=
7
2
\lim_{x \to 0^-} \frac{7}{2} = \frac{7}{2}
x
→
0
−
lim
2
7
=
2
7
More at x→0 from the left
lim
x
→
0
+
7
2
=
7
2
\lim_{x \to 0^+} \frac{7}{2} = \frac{7}{2}
x
→
0
+
lim
2
7
=
2
7
More at x→0 from the right
lim
x
→
1
−
7
2
=
7
2
\lim_{x \to 1^-} \frac{7}{2} = \frac{7}{2}
x
→
1
−
lim
2
7
=
2
7
More at x→1 from the left
lim
x
→
1
+
7
2
=
7
2
\lim_{x \to 1^+} \frac{7}{2} = \frac{7}{2}
x
→
1
+
lim
2
7
=
2
7
More at x→1 from the right
lim
x
→
−
∞
7
2
=
7
2
\lim_{x \to -\infty} \frac{7}{2} = \frac{7}{2}
x
→
−
∞
lim
2
7
=
2
7
More at x→-oo
Rapid solution
[src]
7/2
7
2
\frac{7}{2}
2
7
Expand and simplify
The graph