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Limit of the function
:
Limit of 7^(1/(-3+x))
Limit of (3-3*x^2+4*x^4+6*x^3)/(2*x^2+7*x^4)
Limit of ((5+4*x)/(-1+5*x))^(1+3*x)
Limit of (-6-x^2-3*x+4*x^3)/(3-x^2+2*x^3)
The double integral of
:
7/2
Sum of series
:
7/2
Identical expressions
seven / two
7 divide by 2
seven divide by two
Limit of the function
/
7/2
Limit of the function 7/2
at
→
Calculate the limit!
v
For end points:
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From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
lim (7/2) x->oo
$$\lim_{x \to \infty} \frac{7}{2}$$
Limit(7/2, x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty} \frac{7}{2} = \frac{7}{2}$$
$$\lim_{x \to 0^-} \frac{7}{2} = \frac{7}{2}$$
More at x→0 from the left
$$\lim_{x \to 0^+} \frac{7}{2} = \frac{7}{2}$$
More at x→0 from the right
$$\lim_{x \to 1^-} \frac{7}{2} = \frac{7}{2}$$
More at x→1 from the left
$$\lim_{x \to 1^+} \frac{7}{2} = \frac{7}{2}$$
More at x→1 from the right
$$\lim_{x \to -\infty} \frac{7}{2} = \frac{7}{2}$$
More at x→-oo
Rapid solution
[src]
7/2
$$\frac{7}{2}$$
Expand and simplify
The graph