Mister Exam
Other calculators:
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How to use it?
- Limit of the function:
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Limit of (-exp(-x)+exp(x))/(exp(x)+exp(-x))
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Limit of (3+3*x^3+5*x+5*x^2)/(-1+x^2)
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Limit of (3-x^2+5*x)/(4*x^7+81*x)
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Limit of -cos(1/x)+2*x*sin(1/x)
- Sum of series:
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1/(8+x)
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Identical expressions
- one /(eight +x)
- 1 divide by (8 plus x)
- one divide by (eight plus x)
- 1/8+x
- 1 divide by (8+x)
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Similar expressions
- (-1/8+x^3)/(1/2-x)
- 1/8+x^3-x
- 1/(8-x)
- (-1/8+x^3)/(-1/3+x)
- (x^2*(1/8+x)^(1/3)+cos(x))^(3*atan(1/x)/x^3)
- (-1/8+x^(-3))/(-2+x)
Limit of the function 1/(8+x)
The solution
You have entered
[src]
1 lim ----- x->-8+8 + x
$$\lim_{x \to -8^+} \frac{1}{x + 8}$$
Limit(1/(8 + x), x, -8)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
One‐sided limits
[src]
1 lim ----- x->-8+8 + x
$$\lim_{x \to -8^+} \frac{1}{x + 8}$$
oo
$$\infty$$
= 151.0
1 lim ----- x->-8-8 + x
$$\lim_{x \to -8^-} \frac{1}{x + 8}$$
-oo
$$-\infty$$
= -151.0
= -151.0
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to -8^-} \frac{1}{x + 8} = \infty$$
More at x→-8 from the left
$$\lim_{x \to -8^+} \frac{1}{x + 8} = \infty$$
$$\lim_{x \to \infty} \frac{1}{x + 8} = 0$$
More at x→oo
$$\lim_{x \to 0^-} \frac{1}{x + 8} = \frac{1}{8}$$
More at x→0 from the left
$$\lim_{x \to 0^+} \frac{1}{x + 8} = \frac{1}{8}$$
More at x→0 from the right
$$\lim_{x \to 1^-} \frac{1}{x + 8} = \frac{1}{9}$$
More at x→1 from the left
$$\lim_{x \to 1^+} \frac{1}{x + 8} = \frac{1}{9}$$
More at x→1 from the right
$$\lim_{x \to -\infty} \frac{1}{x + 8} = 0$$
More at x→-oo
More at x→-8 from the left
$$\lim_{x \to -8^+} \frac{1}{x + 8} = \infty$$
$$\lim_{x \to \infty} \frac{1}{x + 8} = 0$$
More at x→oo
$$\lim_{x \to 0^-} \frac{1}{x + 8} = \frac{1}{8}$$
More at x→0 from the left
$$\lim_{x \to 0^+} \frac{1}{x + 8} = \frac{1}{8}$$
More at x→0 from the right
$$\lim_{x \to 1^-} \frac{1}{x + 8} = \frac{1}{9}$$
More at x→1 from the left
$$\lim_{x \to 1^+} \frac{1}{x + 8} = \frac{1}{9}$$
More at x→1 from the right
$$\lim_{x \to -\infty} \frac{1}{x + 8} = 0$$
More at x→-oo
The graph