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(9-x^2)/(-1+x)

Limit of the function (9-x^2)/(-1+x)

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The solution

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      /     2\
      |9 - x |
 lim  |------|
x->-3+\-1 + x/
$$\lim_{x \to -3^+}\left(\frac{9 - x^{2}}{x - 1}\right)$$
Limit((9 - x^2)/(-1 + x), x, -3)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
0
$$0$$
One‐sided limits [src]
      /     2\
      |9 - x |
 lim  |------|
x->-3+\-1 + x/
$$\lim_{x \to -3^+}\left(\frac{9 - x^{2}}{x - 1}\right)$$
0
$$0$$
= -8.76240875132239e-33
      /     2\
      |9 - x |
 lim  |------|
x->-3-\-1 + x/
$$\lim_{x \to -3^-}\left(\frac{9 - x^{2}}{x - 1}\right)$$
0
$$0$$
= 6.95101885901126e-32
= 6.95101885901126e-32
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to -3^-}\left(\frac{9 - x^{2}}{x - 1}\right) = 0$$
More at x→-3 from the left
$$\lim_{x \to -3^+}\left(\frac{9 - x^{2}}{x - 1}\right) = 0$$
$$\lim_{x \to \infty}\left(\frac{9 - x^{2}}{x - 1}\right) = -\infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(\frac{9 - x^{2}}{x - 1}\right) = -9$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\frac{9 - x^{2}}{x - 1}\right) = -9$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(\frac{9 - x^{2}}{x - 1}\right) = -\infty$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\frac{9 - x^{2}}{x - 1}\right) = \infty$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\frac{9 - x^{2}}{x - 1}\right) = \infty$$
More at x→-oo
Numerical answer [src]
-8.76240875132239e-33
-8.76240875132239e-33
The graph
Limit of the function (9-x^2)/(-1+x)