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(-2+x)/(2+sqrt(x))

Limit of the function (-2+x)/(2+sqrt(x))

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The solution

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     /  -2 + x \
 lim |---------|
x->2+|      ___|
     \2 + \/ x /
$$\lim_{x \to 2^+}\left(\frac{x - 2}{\sqrt{x} + 2}\right)$$
Limit((-2 + x)/(2 + sqrt(x)), x, 2)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
0
$$0$$
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 2^-}\left(\frac{x - 2}{\sqrt{x} + 2}\right) = 0$$
More at x→2 from the left
$$\lim_{x \to 2^+}\left(\frac{x - 2}{\sqrt{x} + 2}\right) = 0$$
$$\lim_{x \to \infty}\left(\frac{x - 2}{\sqrt{x} + 2}\right) = \infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(\frac{x - 2}{\sqrt{x} + 2}\right) = -1$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\frac{x - 2}{\sqrt{x} + 2}\right) = -1$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(\frac{x - 2}{\sqrt{x} + 2}\right) = - \frac{1}{3}$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\frac{x - 2}{\sqrt{x} + 2}\right) = - \frac{1}{3}$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\frac{x - 2}{\sqrt{x} + 2}\right) = \infty i$$
More at x→-oo
One‐sided limits [src]
     /  -2 + x \
 lim |---------|
x->2+|      ___|
     \2 + \/ x /
$$\lim_{x \to 2^+}\left(\frac{x - 2}{\sqrt{x} + 2}\right)$$
0
$$0$$
= 1.97610682759051e-32
     /  -2 + x \
 lim |---------|
x->2-|      ___|
     \2 + \/ x /
$$\lim_{x \to 2^-}\left(\frac{x - 2}{\sqrt{x} + 2}\right)$$
0
$$0$$
= -1.26331126049591e-33
= -1.26331126049591e-33
Numerical answer [src]
1.97610682759051e-32
1.97610682759051e-32
The graph
Limit of the function (-2+x)/(2+sqrt(x))