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(-1+x)/log(x)

Limit of the function (-1+x)/log(x)

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The solution

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     /-1 + x\
 lim |------|
x->1+\log(x)/
limx1+(x1log(x))\lim_{x \to 1^+}\left(\frac{x - 1}{\log{\left(x \right)}}\right)
Limit((-1 + x)/log(x), x, 1)
Lopital's rule
We have indeterminateness of type
0/0,

i.e. limit for the numerator is
limx1+(x1)=0\lim_{x \to 1^+}\left(x - 1\right) = 0
and limit for the denominator is
limx1+log(x)=0\lim_{x \to 1^+} \log{\left(x \right)} = 0
Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
limx1+(x1log(x))\lim_{x \to 1^+}\left(\frac{x - 1}{\log{\left(x \right)}}\right)
=
limx1+(ddx(x1)ddxlog(x))\lim_{x \to 1^+}\left(\frac{\frac{d}{d x} \left(x - 1\right)}{\frac{d}{d x} \log{\left(x \right)}}\right)
=
limx1+x\lim_{x \to 1^+} x
=
limx1+x\lim_{x \to 1^+} x
=
11
It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)
The graph
-2.0-1.5-1.0-0.52.00.00.51.01.502
One‐sided limits [src]
     /-1 + x\
 lim |------|
x->1+\log(x)/
limx1+(x1log(x))\lim_{x \to 1^+}\left(\frac{x - 1}{\log{\left(x \right)}}\right)
1
11
= 1.0
     /-1 + x\
 lim |------|
x->1-\log(x)/
limx1(x1log(x))\lim_{x \to 1^-}\left(\frac{x - 1}{\log{\left(x \right)}}\right)
1
11
= 1.0
= 1.0
Rapid solution [src]
1
11
Other limits x→0, -oo, +oo, 1
limx1(x1log(x))=1\lim_{x \to 1^-}\left(\frac{x - 1}{\log{\left(x \right)}}\right) = 1
More at x→1 from the left
limx1+(x1log(x))=1\lim_{x \to 1^+}\left(\frac{x - 1}{\log{\left(x \right)}}\right) = 1
limx(x1log(x))=\lim_{x \to \infty}\left(\frac{x - 1}{\log{\left(x \right)}}\right) = \infty
More at x→oo
limx0(x1log(x))=0\lim_{x \to 0^-}\left(\frac{x - 1}{\log{\left(x \right)}}\right) = 0
More at x→0 from the left
limx0+(x1log(x))=0\lim_{x \to 0^+}\left(\frac{x - 1}{\log{\left(x \right)}}\right) = 0
More at x→0 from the right
limx(x1log(x))=\lim_{x \to -\infty}\left(\frac{x - 1}{\log{\left(x \right)}}\right) = -\infty
More at x→-oo
Numerical answer [src]
1.0
1.0
The graph
Limit of the function (-1+x)/log(x)