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-1+cos(x)

Limit of the function -1+cos(x)

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 lim (-1 + cos(x))
x->0+             
$$\lim_{x \to 0^+}\left(\cos{\left(x \right)} - 1\right)$$
Limit(-1 + cos(x), x, 0)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 0^-}\left(\cos{\left(x \right)} - 1\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\cos{\left(x \right)} - 1\right) = 0$$
$$\lim_{x \to \infty}\left(\cos{\left(x \right)} - 1\right) = \left\langle -2, 0\right\rangle$$
More at x→oo
$$\lim_{x \to 1^-}\left(\cos{\left(x \right)} - 1\right) = -1 + \cos{\left(1 \right)}$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\cos{\left(x \right)} - 1\right) = -1 + \cos{\left(1 \right)}$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\cos{\left(x \right)} - 1\right) = \left\langle -2, 0\right\rangle$$
More at x→-oo
Rapid solution [src]
0
$$0$$
One‐sided limits [src]
 lim (-1 + cos(x))
x->0+             
$$\lim_{x \to 0^+}\left(\cos{\left(x \right)} - 1\right)$$
0
$$0$$
= -1.52456005578576e-32
 lim (-1 + cos(x))
x->0-             
$$\lim_{x \to 0^-}\left(\cos{\left(x \right)} - 1\right)$$
0
$$0$$
= -1.52456005578576e-32
= -1.52456005578576e-32
Numerical answer [src]
-1.52456005578576e-32
-1.52456005578576e-32
The graph
Limit of the function -1+cos(x)