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log(3-x)

Limit of the function log(3-x)

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 lim log(3 - x)
x->2+          
$$\lim_{x \to 2^+} \log{\left(3 - x \right)}$$
Limit(log(3 - x), x, 2)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
One‐sided limits [src]
 lim log(3 - x)
x->2+          
$$\lim_{x \to 2^+} \log{\left(3 - x \right)}$$
0
$$0$$
= -7.22489922557688e-34
 lim log(3 - x)
x->2-          
$$\lim_{x \to 2^-} \log{\left(3 - x \right)}$$
0
$$0$$
= 9.54288936740968e-30
= 9.54288936740968e-30
Rapid solution [src]
0
$$0$$
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 2^-} \log{\left(3 - x \right)} = 0$$
More at x→2 from the left
$$\lim_{x \to 2^+} \log{\left(3 - x \right)} = 0$$
$$\lim_{x \to \infty} \log{\left(3 - x \right)} = \infty$$
More at x→oo
$$\lim_{x \to 0^-} \log{\left(3 - x \right)} = \log{\left(3 \right)}$$
More at x→0 from the left
$$\lim_{x \to 0^+} \log{\left(3 - x \right)} = \log{\left(3 \right)}$$
More at x→0 from the right
$$\lim_{x \to 1^-} \log{\left(3 - x \right)} = \log{\left(2 \right)}$$
More at x→1 from the left
$$\lim_{x \to 1^+} \log{\left(3 - x \right)} = \log{\left(2 \right)}$$
More at x→1 from the right
$$\lim_{x \to -\infty} \log{\left(3 - x \right)} = \infty$$
More at x→-oo
Numerical answer [src]
-7.22489922557688e-34
-7.22489922557688e-34
The graph
Limit of the function log(3-x)