Mister Exam
Other calculators:
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How to use it?
- Limit of the function:
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Limit of sin(3)^2/x
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Limit of x^4+2*cos(x)^2
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Limit of x*2^x*3^(-x)
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Limit of log(1+3*x^2)/(x^3-5*x^2)
- Derivative of:
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log(1-2*x)
- Graphing y =:
- log(1-2*x)
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Identical expressions
- log(one - two *x)
- logarithm of (1 minus 2 multiply by x)
- logarithm of (one minus two multiply by x)
- log(1-2x)
- log1-2x
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Similar expressions
- log(1+2*x)
- log(1-2^x)/log(1+8^x)
- (e^(2*x))^(1/log(1-2*x^2))
Limit of the function log(1-2*x)
The solution
You have entered
[src]
lim log(1 - 2*x) x->0+
$$\lim_{x \to 0^+} \log{\left(- 2 x + 1 \right)}$$
Limit(log(1 - 2*x), x, 0)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 0^-} \log{\left(- 2 x + 1 \right)} = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+} \log{\left(- 2 x + 1 \right)} = 0$$
$$\lim_{x \to \infty} \log{\left(- 2 x + 1 \right)} = \infty$$
More at x→oo
$$\lim_{x \to 1^-} \log{\left(- 2 x + 1 \right)} = i \pi$$
More at x→1 from the left
$$\lim_{x \to 1^+} \log{\left(- 2 x + 1 \right)} = i \pi$$
More at x→1 from the right
$$\lim_{x \to -\infty} \log{\left(- 2 x + 1 \right)} = \infty$$
More at x→-oo
More at x→0 from the left
$$\lim_{x \to 0^+} \log{\left(- 2 x + 1 \right)} = 0$$
$$\lim_{x \to \infty} \log{\left(- 2 x + 1 \right)} = \infty$$
More at x→oo
$$\lim_{x \to 1^-} \log{\left(- 2 x + 1 \right)} = i \pi$$
More at x→1 from the left
$$\lim_{x \to 1^+} \log{\left(- 2 x + 1 \right)} = i \pi$$
More at x→1 from the right
$$\lim_{x \to -\infty} \log{\left(- 2 x + 1 \right)} = \infty$$
More at x→-oo
One‐sided limits
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lim log(1 - 2*x) x->0+
$$\lim_{x \to 0^+} \log{\left(- 2 x + 1 \right)}$$
0
$$0$$
= -0.0865450113393343
lim log(1 - 2*x) x->0-
$$\lim_{x \to 0^-} \log{\left(- 2 x + 1 \right)}$$
0
$$0$$
= 6.7517030308139e-27
= 6.7517030308139e-27
The graph