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Limit of the function
:
Limit of (1+x^2+9*x)/(-5+2*x+7*x^2)
Limit of (-8+x^2+2*x)/(-2+x)
Limit of (4-x^2)/(3-x^2)
Limit of (h-5*h^2+2*h^3)/(h^4-h^2)
Derivative of
:
5/2
Integral of d{x}
:
5/2
Sum of series
:
5/2
Identical expressions
five / two
5 divide by 2
five divide by two
Limit of the function
/
5/2
Limit of the function 5/2
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
lim (5/2) x->oo
$$\lim_{x \to \infty} \frac{5}{2}$$
Limit(5/2, x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
5/2
$$\frac{5}{2}$$
Expand and simplify
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty} \frac{5}{2} = \frac{5}{2}$$
$$\lim_{x \to 0^-} \frac{5}{2} = \frac{5}{2}$$
More at x→0 from the left
$$\lim_{x \to 0^+} \frac{5}{2} = \frac{5}{2}$$
More at x→0 from the right
$$\lim_{x \to 1^-} \frac{5}{2} = \frac{5}{2}$$
More at x→1 from the left
$$\lim_{x \to 1^+} \frac{5}{2} = \frac{5}{2}$$
More at x→1 from the right
$$\lim_{x \to -\infty} \frac{5}{2} = \frac{5}{2}$$
More at x→-oo
The graph