Let's take the limit n→∞lim(n25) Let's divide numerator and denominator by n^2: n→∞lim(n25) = n→∞lim(15n21) Do Replacement u=n1 then n→∞lim(15n21)=u→0+lim(5u2) = 5⋅02=0
The final answer: n→∞lim(n25)=0
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type