Integral of yln(x) dy
The solution
Detail solution
-
The integral of a constant times a function is the constant times the integral of the function:
∫ylog(x)dy=log(x)∫ydy
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The integral of yn is n+1yn+1 when n=−1:
∫ydy=2y2
So, the result is: 2y2log(x)
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Add the constant of integration:
2y2log(x)+constant
The answer is:
2y2log(x)+constant
The answer (Indefinite)
[src]
/ 2
| y *log(x)
| y*log(x) dy = C + ---------
| 2
/
∫ylog(x)dy=C+2y2log(x)
x*log(x) log(x)
-------- - ------
2 2
2*x
2xlog(x)−2x2log(x)
=
x*log(x) log(x)
-------- - ------
2 2
2*x
2xlog(x)−2x2log(x)
x*log(x)/2 - log(x)/(2*x^2)
Use the examples entering the upper and lower limits of integration.