Integral of y*(x^2/2+x) dy
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫y(2x2+x)dy=(2x2+x)∫ydy
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The integral of yn is n+1yn+1 when n=−1:
∫ydy=2y2
So, the result is: 2y2(2x2+x)
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Now simplify:
4xy2(x+2)
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Add the constant of integration:
4xy2(x+2)+constant
The answer is:
4xy2(x+2)+constant
The answer (Indefinite)
[src]
/ / 2 \
| 2 |x |
| / 2 \ y *|-- + x|
| |x | \2 /
| y*|-- + x| dy = C + -----------
| \2 / 2
|
/
∫y(2x2+x)dy=C+2y2(2x2+x)
4x2+2x
=
4x2+2x
Use the examples entering the upper and lower limits of integration.