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y=4cosx+sin3x−8x.

Integral of y=4cosx+sin3x−8x. dx

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The solution

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 |  (4*cos(x) + sin(3*x) - 8*x) dx
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01(8x+sin(3x)+4cos(x))dx\int\limits_{0}^{1} \left(- 8 x + \sin{\left(3 x \right)} + 4 \cos{\left(x \right)}\right)\, dx
Integral(4*cos(x) + sin(3*x) - 8*x, (x, 0, 1))
Detail solution
  1. Integrate term-by-term:

    1. The integral of a constant times a function is the constant times the integral of the function:

      (8x)dx=8xdx\int \left(- 8 x\right)\, dx = - \int 8 x\, dx

      1. The integral of a constant times a function is the constant times the integral of the function:

        8xdx=8xdx\int 8 x\, dx = 8 \int x\, dx

        1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

          xdx=x22\int x\, dx = \frac{x^{2}}{2}

        So, the result is: 4x24 x^{2}

      So, the result is: 4x2- 4 x^{2}

    1. Let u=3xu = 3 x.

      Then let du=3dxdu = 3 dx and substitute du3\frac{du}{3}:

      sin(u)9du\int \frac{\sin{\left(u \right)}}{9}\, du

      1. The integral of a constant times a function is the constant times the integral of the function:

        sin(u)3du=sin(u)du3\int \frac{\sin{\left(u \right)}}{3}\, du = \frac{\int \sin{\left(u \right)}\, du}{3}

        1. The integral of sine is negative cosine:

          sin(u)du=cos(u)\int \sin{\left(u \right)}\, du = - \cos{\left(u \right)}

        So, the result is: cos(u)3- \frac{\cos{\left(u \right)}}{3}

      Now substitute uu back in:

      cos(3x)3- \frac{\cos{\left(3 x \right)}}{3}

    1. The integral of a constant times a function is the constant times the integral of the function:

      4cos(x)dx=4cos(x)dx\int 4 \cos{\left(x \right)}\, dx = 4 \int \cos{\left(x \right)}\, dx

      1. The integral of cosine is sine:

        cos(x)dx=sin(x)\int \cos{\left(x \right)}\, dx = \sin{\left(x \right)}

      So, the result is: 4sin(x)4 \sin{\left(x \right)}

    The result is: 4x2+4sin(x)cos(3x)3- 4 x^{2} + 4 \sin{\left(x \right)} - \frac{\cos{\left(3 x \right)}}{3}

  2. Add the constant of integration:

    4x2+4sin(x)cos(3x)3+constant- 4 x^{2} + 4 \sin{\left(x \right)} - \frac{\cos{\left(3 x \right)}}{3}+ \mathrm{constant}


The answer is:

4x2+4sin(x)cos(3x)3+constant- 4 x^{2} + 4 \sin{\left(x \right)} - \frac{\cos{\left(3 x \right)}}{3}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                                               
 |                                         2              cos(3*x)
 | (4*cos(x) + sin(3*x) - 8*x) dx = C - 4*x  + 4*sin(x) - --------
 |                                                           3    
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cos(3x)3+4sinx4x2-{{\cos \left(3\,x\right)}\over{3}}+4\,\sin x-4\,x^2
The graph
0.001.000.100.200.300.400.500.600.700.800.90-1010
The answer [src]
  11              cos(3)
- -- + 4*sin(1) - ------
  3                 3   
cos312sin1+113-{{\cos 3-12\,\sin 1+11}\over{3}}
=
=
  11              cos(3)
- -- + 4*sin(1) - ------
  3                 3   
113cos(3)3+4sin(1)- \frac{11}{3} - \frac{\cos{\left(3 \right)}}{3} + 4 \sin{\left(1 \right)}
Numerical answer [src]
0.0292147714317345
0.0292147714317345
The graph
Integral of y=4cosx+sin3x−8x. dx

    Use the examples entering the upper and lower limits of integration.