Integral of ycos^2x dy
The solution
Detail solution
-
The integral of a constant times a function is the constant times the integral of the function:
∫ycos2(x)dy=cos2(x)∫ydy
-
The integral of yn is n+1yn+1 when n=−1:
∫ydy=2y2
So, the result is: 2y2cos2(x)
-
Add the constant of integration:
2y2cos2(x)+constant
The answer is:
2y2cos2(x)+constant
The answer (Indefinite)
[src]
/
| 2 2
| 2 y *cos (x)
| y*cos (x) dy = C + ----------
| 2
/
∫ycos2(x)dy=C+2y2cos2(x)
2cos2(x)
=
2cos2(x)
Use the examples entering the upper and lower limits of integration.