Integral of y dy

You have entered [src]

$$\int\limits_{0}^{1} y\, dy$$

Integral(y, (y, 0, 1))

Detail solution

The integral of $y^{n}$ is $\frac{y^{n + 1}}{n + 1}$ when $n \neq -1$ :

$\int y\, dy = \frac{y^{2}}{2}$
Add the constant of integration:

$\frac{y^{2}}{2}+ \mathrm{constant}$

The answer is:

$\frac{y^{2}}{2}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /            2
 |            y 
 | y dy = C + --
 |            2 
/

$${{y^2}\over{2}}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

1/2

$${{1}\over{2}}$$

1/2

$$\frac{1}{2}$$

Simplify

Numerical answer [src]

0.5

0.5

The graph

Use the examples entering the upper and lower limits of integration.