Integral of xdx/sqrt(x+1) dx
The solution
Detail solution
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Let u=x+1.
Then let du=2x+1dx and substitute du:
∫(2u2−2)du
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫2u2du=2∫u2du
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The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: 32u3
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The integral of a constant is the constant times the variable of integration:
∫(−2)du=−2u
The result is: 32u3−2u
Now substitute u back in:
32(x+1)23−2x+1
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Now simplify:
32(x−2)x+1
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Add the constant of integration:
32(x−2)x+1+constant
The answer is:
32(x−2)x+1+constant
The answer (Indefinite)
[src]
/
| 3/2
| x _______ 2*(x + 1)
| --------- dx = C - 2*\/ x + 1 + ------------
| _______ 3
| \/ x + 1
|
/
∫x+1xdx=C+32(x+1)23−2x+1
The graph
Use the examples entering the upper and lower limits of integration.