Integral of x^2+7x dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
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The integral of a constant times a function is the constant times the integral of the function:
∫7xdx=7∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 27x2
The result is: 3x3+27x2
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Now simplify:
6x2⋅(2x+21)
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Add the constant of integration:
6x2⋅(2x+21)+constant
The answer is:
6x2⋅(2x+21)+constant
The answer (Indefinite)
[src]
/
| 3 2
| / 2 \ x 7*x
| \x + 7*x/ dx = C + -- + ----
| 3 2
/
∫(x2+7x)dx=C+3x3+27x2
The graph
Use the examples entering the upper and lower limits of integration.