Integral of x^2+3x+2 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
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The integral of a constant times a function is the constant times the integral of the function:
∫3xdx=3∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 23x2
The result is: 3x3+23x2
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The integral of a constant is the constant times the variable of integration:
∫2dx=2x
The result is: 3x3+23x2+2x
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Now simplify:
6x(2x2+9x+12)
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Add the constant of integration:
6x(2x2+9x+12)+constant
The answer is:
6x(2x2+9x+12)+constant
The answer (Indefinite)
[src]
/
| 3 2
| / 2 \ x 3*x
| \x + 3*x + 2/ dx = C + 2*x + -- + ----
| 3 2
/
∫((x2+3x)+2)dx=C+3x3+23x2+2x
The graph
Use the examples entering the upper and lower limits of integration.