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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of -e^x
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Integral of -15x^2
- Integral of xcoskx
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Integral of xe^(1-x)
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Identical expressions
- (√(x^ two - nine))/x^ two
- (√(x squared minus 9)) divide by x squared
- (√(x to the power of two minus nine)) divide by x to the power of two
- (√(x2-9))/x2
- √x2-9/x2
- (√(x²-9))/x²
- (√(x to the power of 2-9))/x to the power of 2
- √x^2-9/x^2
- (√(x^2-9)) divide by x^2
- (√(x^2-9))/x^2dx
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Similar expressions
- (√(x^2+9))/x^2
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What you mean?
- sqrt(x^2 - 1*9)/(x^2)
- sqrt(x^2 - 1*9)*2/x
- sqrt(x^2 - 1*9)/(x^2)
- sqrt(x^2 - 1*9)*2/x
- sqrt(x^2 - 1*9)/(x^2)
- sqrt(x*(2 - 1*9))/(x^2)
- sqrt(x^2 - 1*9)/(x^2)
You entered:
(√(x^2-9))/x^2
What you mean?
Integral of (√(x^2-9))/x^2 dx
The solution
You have entered
[src]
1 / | | ________ | / 2 | \/ x - 9 | ----------- dx | 2 | x | / 0
$$\int\limits_{0}^{1} \frac{\sqrt{x^{2} - 9}}{x^{2}}\, dx$$
Integral(sqrt(x^2 - 1*9)/(x^2), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | ________ _________ | / 2 / 2 / _________\ | \/ x - 9 \/ -9 + x | / 2 | | ----------- dx = C - ------------ + log\x + \/ -9 + x / | 2 x | x | /
$$\log \left(2\,\sqrt{x^2-9}+2\,x\right)-{{\sqrt{x^2-9}}\over{x}}$$
The graph
The answer
[src]
___ / ___\ oo*I - 2*I*\/ 2 + log\1 + 2*I*\/ 2 /
$${\it \%a}$$
=
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___ / ___\ oo*I - 2*I*\/ 2 + log\1 + 2*I*\/ 2 /
$$- 2 \sqrt{2} i + \log{\left(1 + 2 \sqrt{2} i \right)} + \infty i$$
The graph
Use the examples entering the upper and lower limits of integration.