Integral of x^2/(4-x^2) dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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Rewrite the integrand:
4−x2x2=−1+x+21−x−21
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Integrate term-by-term:
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The integral of a constant is the constant times the variable of integration:
∫(−1)dx=−x
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Let u=x+2.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x+2)
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x−21)dx=−∫x−21dx
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Let u=x−2.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x−2)
So, the result is: −log(x−2)
The result is: −x−log(x−2)+log(x+2)
Method #2
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Rewrite the integrand:
4−x2x2=−x2−4x2
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x2−4x2)dx=−∫x2−4x2dx
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Rewrite the integrand:
x2−4x2=1−x+21+x−21
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Integrate term-by-term:
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x+21)dx=−∫x+21dx
-
Let u=x+2.
Then let du=dx and substitute du:
∫u1du
-
The integral of u1 is log(u).
Now substitute u back in:
log(x+2)
So, the result is: −log(x+2)
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Let u=x−2.
Then let du=dx and substitute du:
∫u1du
-
The integral of u1 is log(u).
Now substitute u back in:
log(x−2)
The result is: x+log(x−2)−log(x+2)
So, the result is: −x−log(x−2)+log(x+2)
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Add the constant of integration:
−x−log(x−2)+log(x+2)+constant
The answer is:
−x−log(x−2)+log(x+2)+constant
The answer (Indefinite)
[src]
/
|
| 2
| x
| ------ dx = C - x - log(-2 + x) + log(2 + x)
| 2
| 4 - x
|
/
∫4−x2x2dx=C−x−log(x−2)+log(x+2)
The graph
−1+log(3)
=
−1+log(3)
Use the examples entering the upper and lower limits of integration.