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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of 1/(1+4x^2)
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Integral of dx/(4x-1)
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Integral of (2x+3)/(x^2-5x+6)
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Integral of 2x(x^2+1)
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Identical expressions
- (x^ three +x+ two)/(x^ two -7x+ twelve)
- (x cubed plus x plus 2) divide by (x squared minus 7x plus 12)
- (x to the power of three plus x plus two) divide by (x to the power of two minus 7x plus twelve)
- (x3+x+2)/(x2-7x+12)
- x3+x+2/x2-7x+12
- (x³+x+2)/(x²-7x+12)
- (x to the power of 3+x+2)/(x to the power of 2-7x+12)
- x^3+x+2/x^2-7x+12
- (x^3+x+2) divide by (x^2-7x+12)
- (x^3+x+2)/(x^2-7x+12)dx
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Similar expressions
- (x^3-x+2)/(x^2-7x+12)
- (x^3+x+2)/(x^2-7x-12)
- (x^3+x+2)/(x^2+7x+12)
- (x^3+x-2)/(x^2-7x+12)
Integral of (x^3+x+2)/(x^2-7x+12) dx
The solution
You have entered
[src]
1 / | | 3 | x + x + 2 | ------------- dx | 2 | x - 7*x + 12 | / 0
$$\int\limits_{0}^{1} \frac{x^{3} + x + 2}{x^{2} - 7 x + 12}\, dx$$
Integral((x^3 + x + 2)/(x^2 - 7*x + 12), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 3 2 | x + x + 2 x | ------------- dx = C + -- - 32*log(-3 + x) + 7*x + 70*log(-4 + x) | 2 2 | x - 7*x + 12 | /
$${{x^2+14\,x}\over{2}}-32\,\log \left(x-3\right)+70\,\log \left(x-4
\right)$$
The graph
The answer
[src]
15/2 - 70*log(4) - 32*log(2) + 102*log(3)
$$-70\,\log 4+{{140\,\log 3-64\,\log 2+15}\over{2}}+32\,\log 3$$
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=
15/2 - 70*log(4) - 32*log(2) + 102*log(3)
$$- 70 \log{\left(4 \right)} - 32 \log{\left(2 \right)} + \frac{15}{2} + 102 \log{\left(3 \right)}$$
The graph
Use the examples entering the upper and lower limits of integration.