Integral of x^7*e^(x^4) dx
The solution
Detail solution
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Let u=x4.
Then let du=4x3dx and substitute 4du:
∫4ueudu
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The integral of a constant times a function is the constant times the integral of the function:
∫ueudu=4∫ueudu
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Use integration by parts:
∫udv=uv−∫vdu
Let u(u)=u and let dv(u)=eu.
Then du(u)=1.
To find v(u):
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The integral of the exponential function is itself.
∫eudu=eu
Now evaluate the sub-integral.
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The integral of the exponential function is itself.
∫eudu=eu
So, the result is: 4ueu−4eu
Now substitute u back in:
4x4ex4−4ex4
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Now simplify:
4(x4−1)ex4
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Add the constant of integration:
4(x4−1)ex4+constant
The answer is:
4(x4−1)ex4+constant
The answer (Indefinite)
[src]
/
| / 4\ / 4\
| / 4\ \x / 4 \x /
| 7 \x / e x *e
| x *E dx = C - ----- + --------
| 4 4
/
∫ex4x7dx=C+4x4ex4−4ex4
The graph
Use the examples entering the upper and lower limits of integration.