Integral of x^1/3 dx

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$$\int\limits_{0}^{1} \sqrt[3]{x}\, dx$$

Integral(x^(1/3), (x, 0, 1))

Detail solution

The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :

$\int \sqrt[3]{x}\, dx = \frac{3 x^{\frac{4}{3}}}{4}$
Add the constant of integration:

$\frac{3 x^{\frac{4}{3}}}{4}+ \mathrm{constant}$

The answer is:

$\frac{3 x^{\frac{4}{3}}}{4}+ \mathrm{constant}$

The answer (Indefinite) [src]

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$$\int \sqrt[3]{x}\, dx = C + \frac{3 x^{\frac{4}{3}}}{4}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

3/4

$$\frac{3}{4}$$

3/4

$$\frac{3}{4}$$

3/4

Numerical answer [src]

0.75

0.75

The graph

Use the examples entering the upper and lower limits of integration.