Integral of (x^4+3)*(4x^3dx) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫(x4+3)4x3⋅1dx=4∫x3(x4+3)dx
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There are multiple ways to do this integral.
Method #1
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Let u=x4.
Then let du=4x3dx and substitute du:
∫(4u+43)du
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫4udu=4∫udu
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The integral of un is n+1un+1 when n=−1:
∫udu=2u2
So, the result is: 8u2
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The integral of a constant is the constant times the variable of integration:
∫43du=43u
The result is: 8u2+43u
Now substitute u back in:
8x8+43x4
Method #2
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Rewrite the integrand:
x3(x4+3)=x7+3x3
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫x7dx=8x8
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The integral of a constant times a function is the constant times the integral of the function:
∫3x3dx=3∫x3dx
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
So, the result is: 43x4
The result is: 8x8+43x4
So, the result is: 2x8+3x4
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Now simplify:
2x4(x4+6)
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Add the constant of integration:
2x4(x4+6)+constant
The answer is:
2x4(x4+6)+constant
The answer (Indefinite)
[src]
/
| 8
| / 4 \ 3 x 4
| \x + 3/*4*x *1 dx = C + -- + 3*x
| 2
/
2(x4+3)2
The graph
Use the examples entering the upper and lower limits of integration.