Mister Exam

Other calculators

Integral of x^2cos(3x^3+5) dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 oo                    
  /                    
 |                     
 |   2    /   3    \   
 |  x *cos\3*x  + 5/ dx
 |                     
/                      
1                      
1x2cos(3x3+5)dx\int\limits_{1}^{\infty} x^{2} \cos{\left(3 x^{3} + 5 \right)}\, dx
Integral(x^2*cos(3*x^3 + 5), (x, 1, oo))
Detail solution
  1. Let u=3x3+5u = 3 x^{3} + 5.

    Then let du=9x2dxdu = 9 x^{2} dx and substitute du9\frac{du}{9}:

    cos(u)81du\int \frac{\cos{\left(u \right)}}{81}\, du

    1. The integral of a constant times a function is the constant times the integral of the function:

      cos(u)9du=cos(u)du9\int \frac{\cos{\left(u \right)}}{9}\, du = \frac{\int \cos{\left(u \right)}\, du}{9}

      1. The integral of cosine is sine:

        cos(u)du=sin(u)\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}

      So, the result is: sin(u)9\frac{\sin{\left(u \right)}}{9}

    Now substitute uu back in:

    sin(3x3+5)9\frac{\sin{\left(3 x^{3} + 5 \right)}}{9}

  2. Now simplify:

    sin(3x3+5)9\frac{\sin{\left(3 x^{3} + 5 \right)}}{9}

  3. Add the constant of integration:

    sin(3x3+5)9+constant\frac{\sin{\left(3 x^{3} + 5 \right)}}{9}+ \mathrm{constant}


The answer is:

sin(3x3+5)9+constant\frac{\sin{\left(3 x^{3} + 5 \right)}}{9}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                       
 |                              /   3    \
 |  2    /   3    \          sin\3*x  + 5/
 | x *cos\3*x  + 5/ dx = C + -------------
 |                                 9      
/                                         
x2cos(3x3+5)dx=C+sin(3x3+5)9\int x^{2} \cos{\left(3 x^{3} + 5 \right)}\, dx = C + \frac{\sin{\left(3 x^{3} + 5 \right)}}{9}
The answer [src]
   1   sin(8)  1   sin(8) 
<- - - ------, - - ------>
   9     9     9     9    
19sin(8)9,19sin(8)9\left\langle - \frac{1}{9} - \frac{\sin{\left(8 \right)}}{9}, \frac{1}{9} - \frac{\sin{\left(8 \right)}}{9}\right\rangle
=
=
   1   sin(8)  1   sin(8) 
<- - - ------, - - ------>
   9     9     9     9    
19sin(8)9,19sin(8)9\left\langle - \frac{1}{9} - \frac{\sin{\left(8 \right)}}{9}, \frac{1}{9} - \frac{\sin{\left(8 \right)}}{9}\right\rangle

    Use the examples entering the upper and lower limits of integration.