Integral of xsin5xdx dx
The solution
Detail solution
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=x and let dv(x)=sin(5x).
Then du(x)=1.
To find v(x):
-
Let u=5x.
Then let du=5dx and substitute 5du:
∫25sin(u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫5sin(u)du=5∫sin(u)du
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The integral of sine is negative cosine:
∫sin(u)du=−cos(u)
So, the result is: −5cos(u)
Now substitute u back in:
−5cos(5x)
Now evaluate the sub-integral.
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The integral of a constant times a function is the constant times the integral of the function:
∫(−5cos(5x))dx=−5∫cos(5x)dx
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Let u=5x.
Then let du=5dx and substitute 5du:
∫25cos(u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫5cos(u)du=5∫cos(u)du
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The integral of cosine is sine:
∫cos(u)du=sin(u)
So, the result is: 5sin(u)
Now substitute u back in:
5sin(5x)
So, the result is: −25sin(5x)
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Add the constant of integration:
−5xcos(5x)+25sin(5x)+constant
The answer is:
−5xcos(5x)+25sin(5x)+constant
The answer (Indefinite)
[src]
/
| sin(5*x) x*cos(5*x)
| x*sin(5*x)*1 dx = C + -------- - ----------
| 25 5
/
25sin(5x)−5xcos(5x)
The graph
cos(5) sin(5)
- ------ + ------
5 25
25sin5−5cos5
=
cos(5) sin(5)
- ------ + ------
5 25
−5cos(5)+25sin(5)
Use the examples entering the upper and lower limits of integration.