Mister Exam

Integral of xsin5xdx dx

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The solution

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01xsin(5x)1dx\int\limits_{0}^{1} x \sin{\left(5 x \right)} 1\, dx
Integral(x*sin(5*x)*1, (x, 0, 1))
Detail solution
  1. Use integration by parts:

    udv=uvvdu\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}

    Let u(x)=xu{\left(x \right)} = x and let dv(x)=sin(5x)\operatorname{dv}{\left(x \right)} = \sin{\left(5 x \right)}.

    Then du(x)=1\operatorname{du}{\left(x \right)} = 1.

    To find v(x)v{\left(x \right)}:

    1. Let u=5xu = 5 x.

      Then let du=5dxdu = 5 dx and substitute du5\frac{du}{5}:

      sin(u)25du\int \frac{\sin{\left(u \right)}}{25}\, du

      1. The integral of a constant times a function is the constant times the integral of the function:

        sin(u)5du=sin(u)du5\int \frac{\sin{\left(u \right)}}{5}\, du = \frac{\int \sin{\left(u \right)}\, du}{5}

        1. The integral of sine is negative cosine:

          sin(u)du=cos(u)\int \sin{\left(u \right)}\, du = - \cos{\left(u \right)}

        So, the result is: cos(u)5- \frac{\cos{\left(u \right)}}{5}

      Now substitute uu back in:

      cos(5x)5- \frac{\cos{\left(5 x \right)}}{5}

    Now evaluate the sub-integral.

  2. The integral of a constant times a function is the constant times the integral of the function:

    (cos(5x)5)dx=cos(5x)dx5\int \left(- \frac{\cos{\left(5 x \right)}}{5}\right)\, dx = - \frac{\int \cos{\left(5 x \right)}\, dx}{5}

    1. Let u=5xu = 5 x.

      Then let du=5dxdu = 5 dx and substitute du5\frac{du}{5}:

      cos(u)25du\int \frac{\cos{\left(u \right)}}{25}\, du

      1. The integral of a constant times a function is the constant times the integral of the function:

        cos(u)5du=cos(u)du5\int \frac{\cos{\left(u \right)}}{5}\, du = \frac{\int \cos{\left(u \right)}\, du}{5}

        1. The integral of cosine is sine:

          cos(u)du=sin(u)\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}

        So, the result is: sin(u)5\frac{\sin{\left(u \right)}}{5}

      Now substitute uu back in:

      sin(5x)5\frac{\sin{\left(5 x \right)}}{5}

    So, the result is: sin(5x)25- \frac{\sin{\left(5 x \right)}}{25}

  3. Add the constant of integration:

    xcos(5x)5+sin(5x)25+constant- \frac{x \cos{\left(5 x \right)}}{5} + \frac{\sin{\left(5 x \right)}}{25}+ \mathrm{constant}


The answer is:

xcos(5x)5+sin(5x)25+constant- \frac{x \cos{\left(5 x \right)}}{5} + \frac{\sin{\left(5 x \right)}}{25}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                           
 |                       sin(5*x)   x*cos(5*x)
 | x*sin(5*x)*1 dx = C + -------- - ----------
 |                          25          5     
/                                             
sin(5x)5xcos(5x)25{{\sin \left(5\,x\right)-5\,x\,\cos \left(5\,x\right)}\over{25}}
The graph
0.001.000.100.200.300.400.500.600.700.800.901-1
The answer [src]
  cos(5)   sin(5)
- ------ + ------
    5        25  
sin55cos525{{\sin 5-5\,\cos 5}\over{25}}
=
=
  cos(5)   sin(5)
- ------ + ------
    5        25  
cos(5)5+sin(5)25- \frac{\cos{\left(5 \right)}}{5} + \frac{\sin{\left(5 \right)}}{25}
Numerical answer [src]
-0.0950894080791708
-0.0950894080791708
The graph
Integral of xsin5xdx dx

    Use the examples entering the upper and lower limits of integration.