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- Improper integral
- Double Integral
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How to use it?
- Integral of d{x}:
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Integral of 1/(1+4x^2)
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Integral of dx/(4x-1)
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Integral of (2x+3)/(x^2-5x+6)
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Integral of 2x(x^2+1)
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Identical expressions
- (x+ four)/(x^ two -2x- eight)
- (x plus 4) divide by (x squared minus 2x minus 8)
- (x plus four) divide by (x to the power of two minus 2x minus eight)
- (x+4)/(x2-2x-8)
- x+4/x2-2x-8
- (x+4)/(x²-2x-8)
- (x+4)/(x to the power of 2-2x-8)
- x+4/x^2-2x-8
- (x+4) divide by (x^2-2x-8)
- (x+4)/(x^2-2x-8)dx
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Similar expressions
- (x+4)/(x^2-2x+8)
- (x+4)/(x^2-2*x-8)
- (x+4)/(x^2+2x-8)
- (x-4)/(x^2-2x-8)
Integral of (x+4)/(x^2-2x-8) dx
The solution
You have entered
[src]
1 / | | x + 4 | ------------ dx | 2 | x - 2*x - 8 | / 0
$$\int\limits_{0}^{1} \frac{x + 4}{x^{2} - 2 x - 8}\, dx$$
Integral((x + 4)/(x^2 - 2*x - 1*8), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | x + 4 log(2 + x) 4*log(-4 + x) | ------------ dx = C - ---------- + ------------- | 2 3 3 | x - 2*x - 8 | /
$${{4\,\log \left(x-4\right)}\over{3}}-{{\log \left(x+2\right)}\over{
3}}$$
The graph
The answer
[src]
4*log(4) log(2)
- -------- + ------ + log(3)
3 3
$$-{{4\,\log 4}\over{3}}+\log 3+{{\log 2}\over{3}}$$
=
=
4*log(4) log(2)
- -------- + ------ + log(3)
3 3
$$- \frac{4 \log{\left(4 \right)}}{3} + \frac{\log{\left(2 \right)}}{3} + \log{\left(3 \right)}$$
The graph
Use the examples entering the upper and lower limits of integration.