Integral of x*ln(x^4)dx dx
The solution
Detail solution
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=log(x4) and let dv(x)=x.
Then du(x)=x4.
To find v(x):
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
Now evaluate the sub-integral.
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The integral of a constant times a function is the constant times the integral of the function:
∫2xdx=2∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: x2
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Now simplify:
2x2(log(x4)−2)
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Add the constant of integration:
2x2(log(x4)−2)+constant
The answer is:
2x2(log(x4)−2)+constant
The answer (Indefinite)
[src]
/
| 2 / 4\
| / 4\ 2 x *log\x /
| x*log\x / dx = C - x + ----------
| 2
/
∫xlog(x4)dx=C+2x2log(x4)−x2
The graph
Use the examples entering the upper and lower limits of integration.