Integral of x*arcsin(1/x)dx dx
The solution
Detail solution
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=asin(x1) and let dv(x)=x.
Then du(x)=−x21−x211.
To find v(x):
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
Now evaluate the sub-integral.
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The integral of a constant times a function is the constant times the integral of the function:
∫−21−x211dx=−2∫1−x211dx
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Don't know the steps in finding this integral.
But the integral is
{x2−1i1−x2forx2>1otherwise
So, the result is: −2{x2−1i1−x2forx2>1otherwise
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Now simplify:
⎩⎨⎧2x2asin(x1)+x2−12x2asin(x1)+i1−x2forx2>1otherwise
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Add the constant of integration:
⎩⎨⎧2x2asin(x1)+x2−12x2asin(x1)+i1−x2forx2>1otherwise+constant
The answer is:
⎩⎨⎧2x2asin(x1)+x2−12x2asin(x1)+i1−x2forx2>1otherwise+constant
The answer (Indefinite)
[src]
/ _________
| / 2 | 2|
|\/ -1 + x for |x | > 1
<
/ | ________ 2 /1\
| | / 2 x *asin|-|
| /1\ \I*\/ 1 - x otherwise \x/
| x*asin|-| dx = C + ---------------------------- + ----------
| \x/ 2 2
|
/
∫xasin(x1)dx=C+2x2asin(x1)+2{x2−1i1−x2forx2>1otherwise
The graph
1
/
|
| /1\
| x*asin|-| dx
| \x/
|
/
0
0∫1xasin(x1)dx
=
1
/
|
| /1\
| x*asin|-| dx
| \x/
|
/
0
0∫1xasin(x1)dx
Integral(x*asin(1/x), (x, 0, 1))
(0.785398163397448 - 0.5j)
(0.785398163397448 - 0.5j)
Use the examples entering the upper and lower limits of integration.