1 / | | x | ----- dx | x + 1 | / 0
Integral(x/(x + 1), (x, 0, 1))
Rewrite the integrand:
Integrate term-by-term:
The integral of a constant is the constant times the variable of integration:
The integral of a constant times a function is the constant times the integral of the function:
Let .
Then let and substitute :
The integral of is .
Now substitute back in:
So, the result is:
The result is:
Add the constant of integration:
The answer is:
/ | | x | ----- dx = C + x - log(1 + x) | x + 1 | /
1 - log(2)
=
1 - log(2)
1 - log(2)
Use the examples entering the upper and lower limits of integration.