Integral of x/exp3x^2+4 dx
The solution
Detail solution
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Integrate term-by-term:
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Don't know the steps in finding this integral.
But the integral is
36(−6x−1)e−6x
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The integral of a constant is the constant times the variable of integration:
∫4dx=4x
The result is: 4x+36(−6x−1)e−6x
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Now simplify:
36(144xe6x−6x−1)e−6x
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Add the constant of integration:
36(144xe6x−6x−1)e−6x+constant
The answer is:
36(144xe6x−6x−1)e−6x+constant
The answer (Indefinite)
[src]
/
| -6*x
| / x \ (-1 - 6*x)*e
| |------- + 4| dx = C + 4*x + ----------------
| | 2 | 36
| |/ 3*x\ |
| \\e / /
|
/
∫((e3x)2x+4)dx=C+4x+36(−6x−1)e−6x
The graph
-6
145 7*e
--- - -----
36 36
36145−36e67
=
-6
145 7*e
--- - -----
36 36
36145−36e67
Use the examples entering the upper and lower limits of integration.