Integral of (x³+3x²-2x+3) dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−2x)dx=−2∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −x2
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
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The integral of a constant times a function is the constant times the integral of the function:
∫3x2dx=3∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: x3
The result is: 4x4+x3
The result is: 4x4+x3−x2
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The integral of a constant is the constant times the variable of integration:
∫3dx=3x
The result is: 4x4+x3−x2+3x
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Now simplify:
x(4x3+x2−x+3)
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Add the constant of integration:
x(4x3+x2−x+3)+constant
The answer is:
x(4x3+x2−x+3)+constant
The answer (Indefinite)
[src]
/
| 4
| / 3 2 \ 3 2 x
| \x + 3*x - 2*x + 3/ dx = C + x - x + 3*x + --
| 4
/
∫((−2x+(x3+3x2))+3)dx=C+4x4+x3−x2+3x
The graph
Use the examples entering the upper and lower limits of integration.