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Derivative of:
x²-2x+1
Identical expressions
x²-2x+ one
x² minus 2x plus 1
x² minus 2x plus one
x²-2x+1dx
Similar expressions
x²-2x-1
x²+2x+1

Integral of x²-2x+1 dx

The solution

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  2                  
  /                  
 |                   
 |  / 2          \   
 |  \x  - 2*x + 1/ dx
 |                   
/                    
0

$$\int\limits_{0}^{2} \left(\left(x^{2} - 2 x\right) + 1\right)\, dx$$

Integral(x^2 - 2*x + 1, (x, 0, 2))

Detail solution

Integrate term-by-term:
1. Integrate term-by-term:
  1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :
    
    $\int x^{2}\, dx = \frac{x^{3}}{3}$
  1. The integral of a constant times a function is the constant times the integral of the function:
    
    $\int \left(- 2 x\right)\, dx = - 2 \int x\, dx$
    1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :
      
      $\int x\, dx = \frac{x^{2}}{2}$
    So, the result is: $- x^{2}$
  The result is: $\frac{x^{3}}{3} - x^{2}$
1. The integral of a constant is the constant times the variable of integration:
  
  $\int 1\, dx = x$
The result is: $\frac{x^{3}}{3} - x^{2} + x$
Now simplify:

$x \left(\frac{x^{2}}{3} - x + 1\right)$
Add the constant of integration:

$x \left(\frac{x^{2}}{3} - x + 1\right)+ \mathrm{constant}$

The answer is:

$x \left(\frac{x^{2}}{3} - x + 1\right)+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                                   
 |                                   3
 | / 2          \               2   x 
 | \x  - 2*x + 1/ dx = C + x - x  + --
 |                                  3 
/

$$\int \left(\left(x^{2} - 2 x\right) + 1\right)\, dx = C + \frac{x^{3}}{3} - x^{2} + x$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

2/3

$$\frac{2}{3}$$

2/3

$$\frac{2}{3}$$

2/3

Numerical answer [src]

0.666666666666667

0.666666666666667

Use the examples entering the upper and lower limits of integration.

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Identical expressions

Similar expressions

Integral of x²-2x+1 dx

Limits of integration:

The graph:

Piecewise:

The solution