1 / | | x1 d(x1) | / 0
Integral(x1, (x1, 0, 1))
The integral of is when :
Add the constant of integration:
The answer is:
/ 2 | x1 | x1 d(x1) = C + --- | 2 /
1/2
=
0.5
Use the examples entering the upper and lower limits of integration.