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Integral of 2x^3*x^2 dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫2x2x3dx=2∫x2x3dx
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There are multiple ways to do this integral.
Method #1
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Let u=x2.
Then let du=2xdx and substitute 2du:
∫4u2du
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The integral of a constant times a function is the constant times the integral of the function:
∫2u2du=2∫u2du
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The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: 6u3
Now substitute u back in:
Method #2
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Let u=x3.
Then let du=3x2dx and substitute 3du:
∫9udu
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The integral of a constant times a function is the constant times the integral of the function:
∫3udu=3∫udu
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The integral of un is n+1un+1 when n=−1:
∫udu=2u2
So, the result is: 6u2
Now substitute u back in:
So, the result is: 3x6
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Add the constant of integration:
3x6+constant
The answer is:
3x6+constant
The answer (Indefinite)
[src]
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| 6
| 3 2 x
| 2*x *x dx = C + --
| 3
/
The graph
Use the examples entering the upper and lower limits of integration.