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- Improper integral
- Double Integral
- Triple Integral
- Curvilinear integral
- Derivative Step by Step
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How to use it?
- Integral of d{x}:
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Integral of e^(-x)/sqrt(x)
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Integral of 8/x^2
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Integral of (1+x^2)^0.5
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Integral of 2*t
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Identical expressions
- (two x+ three)/(x^2+2x- eight)
- (2x plus 3) divide by (x squared plus 2x minus 8)
- (two x plus three) divide by (x squared plus 2x minus eight)
- (2x+3)/(x2+2x-8)
- 2x+3/x2+2x-8
- (2x+3)/(x²+2x-8)
- (2x+3)/(x to the power of 2+2x-8)
- 2x+3/x^2+2x-8
- (2x+3) divide by (x^2+2x-8)
- (2x+3)/(x^2+2x-8)dx
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Similar expressions
- (2x+3)/(x^2-2x-8)
- (2x+3)/(x^2+2x+8)
- (2x-3)/(x^2+2x-8)
Integral of (2x+3)/(x^2+2x-8) dx
The solution
You have entered
[src]
1 / | | 2*x + 3 | ------------ dx | 2 | x + 2*x - 8 | / 0
$$\int\limits_{0}^{1} \frac{2 x + 3}{x^{2} + 2 x - 8}\, dx$$
Integral((2*x + 3)/(x^2 + 2*x - 1*8), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 2*x + 3 5*log(4 + x) 7*log(-2 + x) | ------------ dx = C + ------------ + ------------- | 2 6 6 | x + 2*x - 8 | /
$${{5\,\log \left(x+4\right)}\over{6}}+{{7\,\log \left(x-2\right)
}\over{6}}$$
The graph
The answer
[src]
7*log(2) 5*log(4) 5*log(5)
- -------- - -------- + --------
6 6 6
$${{5\,\log 5}\over{6}}-{{5\,\log 4}\over{6}}-{{7\,\log 2}\over{6}}$$
=
=
7*log(2) 5*log(4) 5*log(5)
- -------- - -------- + --------
6 6 6
$$- \frac{5 \log{\left(4 \right)}}{6} - \frac{7 \log{\left(2 \right)}}{6} + \frac{5 \log{\left(5 \right)}}{6}$$
The graph
Use the examples entering the upper and lower limits of integration.