Integral of (2/sin^2x-3e^x) dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−3ex)dx=−∫3exdx
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The integral of a constant times a function is the constant times the integral of the function:
∫3exdx=3∫exdx
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The integral of the exponential function is itself.
∫exdx=ex
So, the result is: 3ex
So, the result is: −3ex
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The integral of a constant times a function is the constant times the integral of the function:
∫sin2(x)2dx=2∫sin2(x)1dx
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Don't know the steps in finding this integral.
But the integral is
−sin(x)cos(x)
So, the result is: −sin(x)2cos(x)
The result is: −3ex−sin(x)2cos(x)
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Now simplify:
−3ex−tan(x)2
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Add the constant of integration:
−3ex−tan(x)2+constant
The answer is:
−3ex−tan(x)2+constant
The answer (Indefinite)
[src]
/
|
| / 2 x\ x 2*cos(x)
| |------- - 3*e | dx = C - 3*e - --------
| | 2 | sin(x)
| \sin (x) /
|
/
−tanx2−3ex
The graph
Use the examples entering the upper and lower limits of integration.