Integral of (12^(sinx))*cosx dx
The solution
Detail solution
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Let u=sin(x).
Then let du=cos(x)dx and substitute du:
∫12udu
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The integral of an exponential function is itself divided by the natural logarithm of the base.
∫12udu=log(12)12u
Now substitute u back in:
log(12)12sin(x)
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Add the constant of integration:
log(12)12sin(x)+constant
The answer is:
log(12)12sin(x)+constant
The answer (Indefinite)
[src]
/
| sin(x)
| sin(x) 12
| 12 *cos(x) dx = C + --------
| log(12)
/
∫12sin(x)cos(x)dx=log(12)12sin(x)+C
The graph
log(12)11
=
log(12)11
Use the examples entering the upper and lower limits of integration.