Integral of 3*x*sin(y)+1 dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫3xsin(y)dx=sin(y)∫3xdx
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The integral of a constant times a function is the constant times the integral of the function:
∫3xdx=3∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 23x2
So, the result is: 23x2sin(y)
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: 23x2sin(y)+x
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Now simplify:
2x(3xsin(y)+2)
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Add the constant of integration:
2x(3xsin(y)+2)+constant
The answer is:
2x(3xsin(y)+2)+constant
The answer (Indefinite)
[src]
/ 2
| 3*x *sin(y)
| (3*x*sin(y) + 1) dx = C + x + -----------
| 2
/
∫(3xsin(y)+1)dx=C+23x2sin(y)+x
23sin(y)+1
=
23sin(y)+1
Use the examples entering the upper and lower limits of integration.