Integral of 3/(x^2-4) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫x2−43dx=3∫x2−41dx
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Rewrite the integrand:
x2−41=4−x+21+x−21
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The integral of a constant times a function is the constant times the integral of the function:
∫4−x+21+x−21dx=4∫(−x+21+x−21)dx
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Integrate term-by-term:
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The integral of x−21 is log(x−2).
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x+21)dx=−∫x+21dx
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The integral of x+21 is log(x+2).
So, the result is: −log(x+2)
The result is: log(x−2)−log(x+2)
So, the result is: 4log(x−2)−4log(x+2)
So, the result is: 43log(x−2)−43log(x+2)
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Add the constant of integration:
43log(x−2)−43log(x+2)+constant
The answer is:
43log(x−2)−43log(x+2)+constant
The answer (Indefinite)
[src]
/
|
| 3 3*log(2 + x) 3*log(-2 + x)
| ------ dx = C - ------------ + -------------
| 2 4 4
| x - 4
|
/
∫x2−43dx=C+43log(x−2)−43log(x+2)
The graph
−43log(3)
=
−43log(3)
Use the examples entering the upper and lower limits of integration.