Integral of (3/sqrt(x)+1/x^2) dx

1. Integrate term-by-term:

   PiecewiseRule(subfunctions=[(ArctanRule(a=1, b=1, c=0, context=1/(x**2), symbol=x), False), (ArccothRule(a=1, b=1, c=0, context=1/(x**2), symbol=x), False), (ArctanhRule(a=1, b=1, c=0, context=1/(x**2), symbol=x), False)], context=1/(x**2), symbol=x)

   1. The integral of a constant times a function is the constant times the integral of the function:

      $$\int \frac{3}{\sqrt{x}}\, dx = 3 \int \frac{1}{\sqrt{x}}\, dx$$

      1. Let $u = \sqrt{x}$.

         Then let $du = \frac{dx}{2 \sqrt{x}}$ and substitute $2 du$:

         $$\int 2\, du$$

         1. The integral of a constant times a function is the constant times the integral of the function:

            $$\text{False}$$

            1. The integral of a constant is the constant times the variable of integration:

               $$\int 1\, du = u$$

            So, the result is: $2 u$

         Now substitute $u$ back in:

         $$2 \sqrt{x}$$

      So, the result is: $6 \sqrt{x}$

   The result is: $\text{NaN}$

2. Add the constant of integration:

   $$\text{NaN}+ \mathrm{constant}$$

The answer is:

$$\text{NaN}+ \mathrm{constant}$$