Integral of 3cosx/3-x dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x)dx=−∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −2x2
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The integral of a constant times a function is the constant times the integral of the function:
∫33cos(x)dx=3∫3cos(x)dx
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The integral of a constant times a function is the constant times the integral of the function:
∫3cos(x)dx=3∫cos(x)dx
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Don't know the steps in finding this integral.
But the integral is
sin(x)
So, the result is: 3sin(x)
So, the result is: sin(x)
The result is: −2x2+sin(x)
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Add the constant of integration:
−2x2+sin(x)+constant
The answer is:
−2x2+sin(x)+constant
The answer (Indefinite)
[src]
/
| 2
| /3*cos(x) \ x
| |-------- - x| dx = C - -- + sin(x)
| \ 3 / 2
|
/
∫(−x+33cos(x))dx=C−2x2+sin(x)
The graph
−21+sin(1)
=
−21+sin(1)
Use the examples entering the upper and lower limits of integration.